The role of the size of the sample


What does it mean that the probability of heads, when you toss an unbiased coin, is fifty percent?

Students work in small groups. They use the TI-83 or TI-84 calculator to simulate 9, 99, and 999 tosses of a coin.  They gather several samples and record the number of (simulated) heads, and the deviation of their frequencies from 50%. They formulate and discuss their observations.

Example of a program:
(In this program percentage is rounded to 1%)
We assign an outcome of 1 to mean heads, and an outcome of 0 to mean tails.  We count the number of ones (heads) in each sample.
Set MODE to Float 0. To get samples of size N = 9, 99, 999, first store 9 or 99 or 999 in N, and then, for each N, run the following sequences of keystrokes:
sum(randInt(0,1,
N))→A:100A/N-50
→B:{A,B}       repeat ENTER 8 times to get 8 samples of each size.

Example of a simulation (deviation from 50% is in parentheses):

N(sample size): 9 99 999
Sample number No. of heads No. of heads No. of heads
1 7(28%) 41(-9%) 478(-2%)
2 3(-17%) 48(-2%) 503(0%)
3 3(-17%) 57(-2%) 512(1%)
4 5(6%) 47(-3%) 486(-1%)
5 3(-17%) 51(2%) 515(2%)
6 5(6%) 52(3%) 531(3%)
7 3(-17%) 40(-10%) 502(0%)
8 4(-6%) 50(1%) 499(-0%)


Some points for discussion.
  (1) In none of the cases is the frequency exactly 50%, because the sizes of the samples were odd numbers.
  (2) Even when the sample is large, a big deviation from 50% is possible, but it is very unlikely.
  (3) When we say that "the probability of heads is 50%", we mean that: When a sample is large, the chance that the frequency is very different from 50% is small.




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