Solving Arithmetic Problems With Two Boards

Students work in pairs. They use two identical boards and only one kind of variable counter, for example, a green square counter named s. The teacher shows students two configurations of counters, one for each board.

Task

Put these configurations on your boards and find the value of the variable token for which both boards have the same value.


Example

2s + 6 + 1 5 + 6 + 3 + 1
Add -7 to each board.

2s + 6 + 1 - 6 - 1 5 + 6 + 3 + 1 - 6 - 1
Regroup 7 - 7 = 0 on both boards.

2s 5 + 3
Regroup 5 + 3 = 2 + 2 + 2 + 2 on rightmost board.

2s 2 + 2 + 2 + 2
Halve the value of both boards.

s 2 + 2

So, s = 4.


Remark

In choosing a task the teacher should pay attention to the range of numbers represented on the boards, in order not to give a task that is impossible.

The Method of Solving These Problems

Regroup the tokens on each board. Remote at the sane time two tokens, one from each board, if they have the same value. Continue until all variable counters remain on one board and all other counters are on the other board. Also on these boards, you can sometimes halve both values or divide them by 3,5, 6, or 10.


Example

5s + 2s 10 + 2 + 1

So, s = 13/7.


Example 2

5s 3 + 3 + 2 + 2
Regroup 3 + 3 + 2 + 2 = 10 on the rightmost board.

5s 10
Divide by 5 on both boards.

s 2

So, s = 2.


The teacher should explain this method to students. But the students need to find how to use it efficiently. So such tasks should be given several times until they become routine.


Examples

6s + 5 + 5 10 + 10 + 10 + 3 + 1
Add -10 to each board.

6s + 5 + 5 - 10 10 + 10 + 10 + 3 + 1 - 10
Regroup 10 - 10 = 0 on both boards.

6s 10 + 10 + 3 + 1
Regroup 10 + 10 + 3 + 1 = 6 + 6 + 6 + 6 on rightmost board.

6s 6 + 6 + 6 + 6
Divide by 6 on both boards.

s 1 + 1 + 1 + 1

So, s = 4.



Webpage Maintained by Owen Ramsey
Number Board index